Hi Sander,
From Harry's website it would appear that he is using a Starlight Express SXVF-M25C 6Mp OSC camera - so I suppose the 'USB Download' overhead might actually be quite significant if anything on his PC 'takes over' during the download phase.
Correct me if my maths is wrong, but I would consider a 6Mp 'RAW' (32-bit data byte) frame from an OSC imager to be of the order of ( 6 x 1024 x 1024 x 4 x 8 ) 'bits' long. So, at the maximum theoretical USB 2.0 transfer rate (of 480Mbps), that would result in a download time of ( 6 x 1024 x 1024 x 4 x 8 ) / ( 480 x 1024 x 1024 ) seconds - i.e. 1/10th of a second. Given that the 'maximum' rate is not really attainable, and allowing for, say, a maximum 'actual' rate of about 33% of 'theoretical', the transfer time should be around 0.3s - assuming that the main CPU and hard-drive can maintain this rate.
Surely therefore there IS scope for an imaging camera that is NOT fitted with a true mechanical shutter to collect, or create, 'noise' during this 0.3 to 0.5 seconds after actual 'photon collection' ought to have ceased?
Perhaps what you need to try Harry, is to run your camera 'flat out', as if you were collecting 'zero exposure time' bias/offset frames. How many frames can you collect in, say, a ten-second period. Run a few trials and see what the average number is. Divide this by '10' (seconds) to get your 'average USB transfer time'. If your imager does NOT have a true mechanical shutter, then this USB transfer time is a period during which your imager will still be collecting photons AND 'noise', on those parts of the pixel array that have still to be 'read out' during the 'USB transfer time' window.
Unless my understanding of how an imager (without a mechanical shutter, or on-board high-speed 'frame-store') works is flawed, then I have always believed that you need to really get the USB transfer time down as low as possible - certainly MUCH lower than the time above which you would be looking to apply Dark Frame correction to your normal subs (which I have always taken to be around 1 second, or so).
Can anyone confirm my understanding - or, better, tell me where I might be going wrong?
Cheers,